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Diesel Fuel – Density – Melting Point – Thermal Conductivity

About Diesel Fuel

In general, diesel fuel is any liquid fuel specifically designed for use in diesel engines, whose fuel ignition takes place, without any spark, as a result of compression of the inlet air mixture and then injection of fuel. Currently, the main source of fuel for road vehicles is petroleum oil. Oil is a naturally occurring, fossil liquid comprising a complex mixture of hydrocarbons of various molecular weights together with various other organic compounds. These components are separated by fractional distillation in an oil refinery in order to produce gasoline, diesel fuel, kerosene and other products.

diesel fuel properties density strength price

Summary

Name Diesel Fuel
Phase at STP liquid
Density 850 kg/m3
Ultimate Tensile Strength N/A
Yield Strength N/A
Young’s Modulus of Elasticity N/A
Brinell Hardness N/A
Melting Point N/A
Thermal Conductivity 0.13 W/mK
Heat Capacity 2100 J/g K
Price 1.1 $/kg

Density of Diesel Fuel

Typical densities of various substances are at atmospheric pressure. Density is defined as the mass per unit volume. It is an intensive property, which is mathematically defined as mass divided by volume:  ρ = m/V

In words, the density (ρ) of a substance is the total mass (m) of that substance divided by the total volume (V) occupied by that substance. The standard SI unit is kilograms per cubic meter (kg/m3). The Standard English unit is pounds mass per cubic foot (lbm/ft3).

Density of Diesel Fuel is 850 kg/m3.

 

Example: Density

Calculate the height of a cube made of Diesel Fuel, which weighs one metric ton.

Solution:

Density is defined as the mass per unit volume. It is mathematically defined as mass divided by volume: ρ = m/V

As the volume of a cube is the third power of its sides (V = a3), the height of this cube can be calculated:

density of material - equation

The height of this cube is then a = 1.056 m.

Density of Materials

Material Table - Density of Materials

 

Thermal Properties of Diesel Fuel

Diesel Fuel – Melting Point

Melting point of Diesel Fuel is N/A.

Note that, these points are associated with the standard atmospheric pressure. In general, melting is a phase change of a substance from the solid to the liquid phase. The melting point of a substance is the temperature at which this phase change occurs. The melting point also defines a condition in which the solid and liquid can exist in equilibrium. For various chemical compounds and alloys, it is difficult to define the melting point, since they are usually a mixture of various chemical elements.

Diesel Fuel – Thermal Conductivity

Thermal conductivity of Diesel Fuel is 0.13 W/(m·K).

The heat transfer characteristics of a solid material are measured by a property called the thermal conductivity, k (or λ), measured in W/m.K. It is a measure of a substance’s ability to transfer heat through a material by conduction. Note that Fourier’s law applies for all matter, regardless of its state (solid, liquid, or gas), therefore, it is also defined for liquids and gases.

The thermal conductivity of most liquids and solids varies with temperature. For vapors, it also depends upon pressure. In general:

thermal conductivity - definition

Most materials are very nearly homogeneous, therefore we can usually write k = k (T). Similar definitions are associated with thermal conductivities in the y- and z-directions (ky, kz), but for an isotropic material the thermal conductivity is independent of the direction of transfer, kx = ky = kz = k.

Diesel Fuel – Specific Heat

Specific heat of Diesel Fuel is 2100 J/g K.

Specific heat, or specific heat capacity, is a property related to internal energy that is very important in thermodynamics. The intensive properties cv and cp are defined for pure, simple compressible substances as partial derivatives of the internal energy u(T, v) and enthalpy h(T, p), respectively:

where the subscripts v and p denote the variables held fixed during differentiation. The properties cv and cp are referred to as specific heats (or heat capacities) because under certain special conditions they relate the temperature change of a system to the amount of energy added by heat transfer. Their SI units are J/kg K or J/mol K.

 

Example: Heat transfer calculation

Diesel Fuel - Thermal ConductivityThermal conductivity is defined as the amount of heat (in watts) transferred through a square area of material of given thickness (in metres) due to a difference in temperature. The lower the thermal conductivity of the material the greater the material’s ability to resist heat transfer.

Calculate the rate of heat flux through a wall 3 m x 10 m in area (A = 30 m2). The wall is 15 cm thick (L1) and it is made of Diesel Fuel with the thermal conductivity of k1 = 0.13 W/m.K (poor thermal insulator). Assume that, the indoor and the outdoor temperatures are 22°C and -8°C, and the convection heat transfer coefficients on the inner and the outer sides are h1 = 10 W/m2K and h2 = 30 W/m2K, respectively. Note that, these convection coefficients strongly depend especially on ambient and interior conditions (wind, humidity, etc.).

Calculate the heat flux (heat loss) through this wall.

Solution:

As was written, many of the heat transfer processes involve composite systems and even involve a combination of both conduction and convection. With these composite systems, it is often convenient to work with an overall heat transfer coefficientknown as a U-factor. The U-factor is defined by an expression analogous to Newton’s law of cooling:

Heat transfer calculation - Newton’s law of cooling

The overall heat transfer coefficient is related to the total thermal resistance and depends on the geometry of the problem.

Assuming one-dimensional heat transfer through the plane wall and disregarding radiation, the overall heat transfer coefficient can be calculated as:

Heat transfer calculation - U-factor

 

The overall heat transfer coefficient is then: U = 1 / (1/10 + 0.15/0.13 + 1/30) = 0.78 W/m2K

The heat flux can be then calculated simply as: q = 0.78 [W/m2K] x 30 [K] = 23.31 W/m2

The total heat loss through this wall will be: qloss = q . A = 23.31 [W/m2] x 30 [m2] = 699.2 W

Melting Point of Materials

Material Table - Melting Point

Thermal Conductivity of Materials

Material Table - Thermal Conductivity

Heat Capacity of Materials

Material Table - Heat Capacity

Strength of Materials

Material Table - Strength of Materials

Elasticity of Materials

Material Table - Elasticity of Materials

Hardness of Materials

Material Table - Hardness of Materials